If the amount is 6 frac{1}{4} times the princ | vedclass

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(D) Let the principal be $P = 100$.The amount $A$ after $2$ years is $6 \frac{1}{4}$ times the principal,so $A = 100 	imes \frac{25}{4} = 625$.The fo

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$150$

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(D) Let the principal be $P = 100$.The amount $A$ after $2$ years is $6 \frac{1}{4}$ times the principal,so $A = 100 	imes \frac{25}{4} = 625$.The formula for compound interest is $A = P(1 + \frac{r}{100})^n$,where $n = 2$.Substituting the values: $625 = 100(1 + \frac{r}{100})^2$.Dividing both sides by $100$: $6.25 = (1 + \frac{r}{100})^2$.Taking the square root of both sides: $\sqrt{6.25} = 1 + \frac{r}{100}$.$2.5 = 1 + \frac{r}{100}$.$1.5 = \frac{r}{100}$.$r = 1.5 	imes 100 = 150 \%$.

If the amount is $6 \frac{1}{4}$ times the principal after $2$ years at compound interest,the rate of interest (in $\%$) per annum is

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