If the angle between the circles $x^2+y^2-12x-6y+41=0$ and $x^2+y^2+kx+6y-59=0$ is $45^{\circ}$,then a value of $k$ is

  • A
    $0$
  • B
    $-4$
  • C
    $-3$
  • D
    $-1$

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