If the charge on the capacitor is increased b | vedclass

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(C) Concept: The energy $U$ stored in a capacitor is given by the formula:$U = \frac{q^2}{2C}$where $q$ is the charge and $C$ is the capacitance.Let t

Vedclass · Accepted Answer

$20$

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(C) Concept: The energy $U$ stored in a capacitor is given by the formula:$U = \frac{q^2}{2C}$where $q$ is the charge and $C$ is the capacitance.Let the original charge be $q$. The initial energy is $U = \frac{q^2}{2C}$.When the charge is increased by $\Delta q = 2 \ C$,the new charge becomes $(q + 2)$.The new energy $U'$ is given as $U' = U + 21\% 	ext{ of } U = 1.21U$.Substituting the formula for energy:$1.21 \left( \frac{q^2}{2C} ight) = \frac{(q + 2)^2}{2C}$$1.21 q^2 = (q + 2)^2$Taking the square root on both sides:$\sqrt{1.21} q = q + 2$$1.1q = q + 2$$0.1q = 2$$q = \frac{2}{0.1} = 20 \ C$.Therefore,the original charge on the capacitor is $20 \ C$.

If the charge on the capacitor is increased by $2 \ C$,the energy stored in it increases by $21 \%$. The original charge on the capacitor is: (in $C$)

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