If the circles $x^2+y^2-2x-2y+k=0$ and $x^2+y^2+4x+6y+4=0$ touch each other externally,then the point of contact of the two circles is

  • A
    $\left(-\frac{1}{5}, -\frac{3}{5}\right)$
  • B
    $\left(-\frac{1}{3}, -\frac{1}{3}\right)$
  • C
    $(-1, -3)$
  • D
    $(-1, -1)$

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