If the coefficient of ${x^7}$ in ${\left( {a{x^2} + \frac{1}{{bx}}} \right)^{11}}$ is equal to the coefficient of ${x^{ - 7}}$ in ${\left( {ax - \frac{1}{{b{x^2}}}} \right)^{11}}$,then $ab =$

  • A
    $1$
  • B
    $1/2$
  • C
    $2$
  • D
    $3$

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