If the coordinates of the points A and B are | vedclass

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(A) The slope of the line $AB$ is $m = \frac{6 - 3}{7 - 3} = \frac{3}{4}$.The equation of the line $AB$ is $y - 3 = \frac{3}{4}(x - 3)$.$4y - 12 = 3x

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$\frac{5}{4}$

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(A) The slope of the line $AB$ is $m = \frac{6 - 3}{7 - 3} = \frac{3}{4}$.The equation of the line $AB$ is $y - 3 = \frac{3}{4}(x - 3)$.$4y - 12 = 3x - 9 \Rightarrow 3x - 4y + 3 = 0$.To find the intercepts,we rewrite the equation as $3x - 4y = -3$,or $\frac{x}{-1} + \frac{y}{3/4} = 1$.The intercepts are $(-1, 0)$ and $(0, 3/4)$.The length of the segment intercepted between the axes is $\sqrt{(-1 - 0)^2 + (0 - 3/4)^2} = \sqrt{1 + \frac{9}{16}} = \sqrt{\frac{25}{16}} = \frac{5}{4}$.

If the coordinates of the points $A$ and $B$ are $(3, 3)$ and $(7, 6)$,then the length of the portion of the line $AB$ intercepted between the axes is

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