If the diagonals of a rhombus are 8 and 6, th | vedclass

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(A) Let the rhombus be $ABCD$ with diagonals $AC = 8$ and $BD = 6.$ The diagonals of a rhombus bisect each other at right angles at point $O.$Therefor

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) Let the rhombus be $ABCD$ with diagonals $AC = 8$ and $BD = 6.$ The diagonals of a rhombus bisect each other at right angles at point $O.$Therefore,$BO = \frac{BD}{2} = \frac{6}{2} = 3$ units and $OC = \frac{AC}{2} = \frac{8}{2} = 4$ units.In the right-angled triangle $	riangle BOC,$ by the Pythagorean theorem:$BC^2 = BO^2 + OC^2$$BC^2 = 3^2 + 4^2$$BC^2 = 9 + 16 = 25$ sq. units.Thus,the square of its side is $25.$

If the diagonals of a rhombus are $8$ and $6,$ then the square of its side is

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