If the dielectric constant of a substance is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The relationship between the dielectric constant $K$ and the electric susceptibility $\chi_{e}$ is given by the formula:$K = 1 + \frac{\chi_{e}}{\

Vedclass · Accepted Answer

$\frac{\varepsilon_0}{3}$

Vedclass · Answer

(A) The relationship between the dielectric constant $K$ and the electric susceptibility $\chi_{e}$ is given by the formula:$K = 1 + \frac{\chi_{e}}{\varepsilon_0}$Given that $K = \frac{4}{3}$,we substitute this value into the equation:$\frac{4}{3} = 1 + \frac{\chi_{e}}{\varepsilon_0}$Subtracting $1$ from both sides:$\frac{\chi_{e}}{\varepsilon_0} = \frac{4}{3} - 1$$\frac{\chi_{e}}{\varepsilon_0} = \frac{1}{3}$Therefore,the electric susceptibility is:$\chi_{e} = \frac{\varepsilon_0}{3}$

If the dielectric constant of a substance is $K = \frac{4}{3}$,then the electric susceptibility $\chi_{e}$ is

Similar Questions

The dielectric constant of a metal is ........ .

Which of the following statements is false in the case of polar molecules?

How does the polarised dielectric modify the original external field inside it?

Choose the correct relation between polarisation $P$ and electric susceptibility $\chi_{e}$ of a dielectric material. ($E =$ electric field)

The dielectric constant for a metal is

Vedclass Test Series

Exam Paper Generator

Online Exam Module