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(C) The dimensions of a physical quantity are given as $[L^{a} M^{b} T^{c}]$.Let us check the dimensions of the given options:$1$. Velocity: $[M^{0} L

Vedclass · Accepted Answer

pressure if $a=-1, b=1, c=-2$

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(C) The dimensions of a physical quantity are given as $[L^{a} M^{b} T^{c}]$.Let us check the dimensions of the given options:$1$. Velocity: $[M^{0} L^{1} T^{-1}]$. Here,$a=1, b=0, c=-1$. Option $A$ is incorrect.$2$. Force: $[M^{1} L^{1} T^{-2}]$. Here,$a=1, b=1, c=-2$. Option $B$ is incorrect.$3$. Pressure: Pressure is defined as $	ext{Force} / 	ext{Area} = [M^{1} L^{1} T^{-2}] / [L^{2}] = [M^{1} L^{-1} T^{-2}]$. Here,$a=-1, b=1, c=-2$. This matches option $C$.$4$. Acceleration: $[M^{0} L^{1} T^{-2}]$. Here,$a=1, b=0, c=-2$. Option $D$ is incorrect.Therefore,the correct option is $C$.

If the dimensions of a physical quantity are given by $[L^{a} M^{b} T^{c}]$,then the physical quantity is:

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