If the distance between $A(-4, -3)$ and $B(6, a)$ is $10$,then $a = \ldots \ldots \ldots . . .$

The points $(-4,0), (4,0), (0,3)$ are the vertices of a

If $A(0, y_{1})$ and $B(0, y_{2})$ are the points on the $Y$-axis,then the distance between them $AB = \ldots$

$A$ circle drawn with the origin as the center passes through $\left(\frac{13}{2}, 0\right)$. The point which does not lie in the interior of the circle is

$(0, 0), (3.1, 0)$ and $(0, 4.5)$ are the vertices of $\ldots \ldots \ldots \ldots$ triangle.

The distance between the points $A(0, 6)$ and $B(0, -2)$ is