If the electric field is given by vec{E} = (5 | vedclass

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(A) The electric flux $\Phi$ is defined as the dot product of the electric field $\vec{E}$ and the area vector $\vec{A}$.Given,$\vec{E} = (5 \hat{i} +

Vedclass · Accepted Answer

$100$

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(A) The electric flux $\Phi$ is defined as the dot product of the electric field $\vec{E}$ and the area vector $\vec{A}$.Given,$\vec{E} = (5 \hat{i} + 4 \hat{j} + 9 \hat{k})$.The surface lies in the $Y-Z$ plane,so its area vector $\vec{A}$ is directed along the $X$-axis.Therefore,$\vec{A} = 20 \hat{i}$ units.The electric flux is calculated as:$\Phi = \vec{E} \cdot \vec{A}$$\Phi = (5 \hat{i} + 4 \hat{j} + 9 \hat{k}) \cdot (20 \hat{i})$Since $\hat{i} \cdot \hat{i} = 1$,$\hat{i} \cdot \hat{j} = 0$,and $\hat{i} \cdot \hat{k} = 0$:$\Phi = 5 	imes 20 = 100$ units.

If the electric field is given by $\vec{E} = (5 \hat{i} + 4 \hat{j} + 9 \hat{k})$. The electric flux through a surface of area $20$ units lying in the $Y-Z$ plane will be (in units):

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