If the feasible region is as shown in the fig | vedclass

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(C) The shaded region is bounded by three lines and the axes in the first quadrant:$1$. The line passing through $(0, 3)$ and $(4, 0)$ is given by $\f

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$3x + 4y \leq 12, y - x \geq 0, y \leq 3, x, y \geq 0$

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(C) The shaded region is bounded by three lines and the axes in the first quadrant:$1$. The line passing through $(0, 3)$ and $(4, 0)$ is given by $\frac{x}{4} + \frac{y}{3} = 1$,which simplifies to $3x + 4y = 12$. Since the shaded region is towards the origin side,the inequality is $3x + 4y \leq 12$.$2$. The line passing through $(0, 0)$ and $(3, 3)$ is $y = x$,which is $y - x = 0$. The shaded region is above this line,so the inequality is $y \geq x$ or $y - x \geq 0$.$3$. The horizontal line passing through $(0, 3)$ is $y = 3$. The shaded region is below this line,so the inequality is $y \leq 3$.$4$. Since the region is in the first quadrant,$x \geq 0$ and $y \geq 0$.Combining these,the inequalities are $3x + 4y \leq 12, y - x \geq 0, y \leq 3, x, y \geq 0$.

If the feasible region is as shown in the figure,then the related inequalities are:

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