If the function defined by $f(x) = \frac{\log (1+x)^{1+x}}{x^2} - \frac{1}{x}, x \neq 0$ is continuous at $x=0$,then $6 f(0)$ is equal to

  • A
    $2$
  • B
    $3$
  • C
    $1$
  • D
    $6$

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