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(D) The maximum line of sight distance $(d_M)$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by the

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$64$

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(D) The maximum line of sight distance $(d_M)$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by the formula: $d_M = \sqrt{2Rh_T} + \sqrt{2Rh_R}$.Given: $h_T = 80\,m$,$h_R = 80\,m$,and $R = 6.4 	imes 10^6\,m$.Substituting the values: $d_M = \sqrt{2 	imes 6.4 	imes 10^6 	imes 80} + \sqrt{2 	imes 6.4 	imes 10^6 	imes 80}$.$d_M = 2 	imes \sqrt{2 	imes 6.4 	imes 10^6 	imes 80} = 2 	imes \sqrt{1024 	imes 10^6} = 2 	imes 32 	imes 10^3\,m$.$d_M = 64 	imes 10^3\,m = 64\,km$.

If the height of transmitting and receiving antennas are $80\,m$ each,the maximum line of sight distance will be $..............\,km$. Given: Earth's radius $= 6.4 \times 10^6\,m$.

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