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(D) Let the point $P$ be $(h, k)$. The length of the tangent from $(h, k)$ to a circle $S=0$ is $\sqrt{S(h, k)}$.Since the lengths of the tangents are

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$(5,2)$

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(D) Let the point $P$ be $(h, k)$. The length of the tangent from $(h, k)$ to a circle $S=0$ is $\sqrt{S(h, k)}$.Since the lengths of the tangents are equal,the power of the point $P$ with respect to all three circles is equal.$S_1(h, k) = S_2(h, k) = S_3(h, k)$.$S_1 \equiv x^2+y^2-4=0$$S_2 \equiv x^2+y^2-2x+3y=0$$S_3 \equiv x^2+y^2+7y-18=0$Equating $S_1 = S_2$:$x^2+y^2-4 = x^2+y^2-2x+3y$$2x-3y-4=0$ $(i)$Equating $S_1 = S_3$:$x^2+y^2-4 = x^2+y^2+7y-18$$-7y+14=0$$y=2$Substituting $y=2$ into $(i)$:$2x-3(2)-4=0$$2x-6-4=0$$2x=10$$x=5$Thus,the coordinates of $P$ are $(5, 2)$.

If the lengths of the tangents drawn from a point $P$ to the three circles $x^2+y^2-4=0$,$x^2+y^2-2x+3y=0$,and $x^2+y^2+7y-18=0$ are equal,then the coordinates of $P$ are

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