If the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-2}{4}$ meets the plane $x+2y+3z=15$ at the point $P$,then the distance of $P$ from the origin is

  • A
    $\frac{7}{2}$ units
  • B
    $\frac{9}{2}$ units
  • C
    $\frac{\sqrt{5}}{2}$ units
  • D
    $2 \sqrt{5}$ units

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