If the line px - qy = r intersects the coordi | vedclass

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(B) The given equation of the line is $px - qy = r$. Since the line intersects the $x$-axis at $(a, 0)$,we substitute $x = a$ and $y = 0$ into the equ

Vedclass · Accepted Answer

$\frac{r(q-p)}{pq}$

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(B) The given equation of the line is $px - qy = r$. Since the line intersects the $x$-axis at $(a, 0)$,we substitute $x = a$ and $y = 0$ into the equation: $p(a) - q(0) = r$ $\Rightarrow pa = r$ $\Rightarrow a = \frac{r}{p}$. Since the line intersects the $y$-axis at $(0, b)$,we substitute $x = 0$ and $y = b$ into the equation: $p(0) - q(b) = r$ $\Rightarrow -qb = r$ $\Rightarrow b = -\frac{r}{q}$. Therefore,the value of $(a + b)$ is: $a + b = \frac{r}{p} - \frac{r}{q} = \frac{rq - rp}{pq} = \frac{r(q - p)}{pq}$.

If the line $px - qy = r$ intersects the coordinate axes at $(a, 0)$ and $(0, b)$,then the value of $(a + b)$ is equal to

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