If the line $4x - 3y + p = 0$ $(p + 3 > 0)$ touches the circle $x^2 + y^2 - 4x + 6y + 4 = 0$ at the point $(h, k)$,then $h - 2k = . . . . . .$

  • A
    $-\frac{8}{5}$
  • B
    $2$
  • C
    $\frac{6}{5}$
  • D
    $3$

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