If the lines $x+y-2=0$,$3x-4y+1=0$ and $5x+ky-7=0$ are concurrent at $(\alpha, \beta)$,then the equation of the line concurrent with the given lines and perpendicular to $kx+y-k=0$ is

If $3x + 6y + 2 = 0$,$x + y + 1 = 0$,and $2x - y + 3 = 0$ are three given lines,then the point $\left(\frac{-4}{3}, \frac{1}{3}\right)$ is

The value of $k$ such that the lines $2x - 3y + k = 0$,$3x - 4y - 13 = 0$,and $8x - 11y - 33 = 0$ are concurrent,is

$(a, b)$ is the point of concurrency of the lines $x-3y+3=0$,$kx+y+k=0$,and $2x+y-8=0$. If the perpendicular distance from the origin to the line $L \equiv ax-by+2k=0$ is $p$,then the perpendicular distance from the point $(2, 3)$ to $L=0$ is

For all values of $a$ and $b$,the line $(a+2b)x + (a-b)y + (a+5b) = 0$ passes through a fixed point. Find that point.

The line parallel to the $x$-axis and passing through the intersection of the lines $ax + 2by + 3b = 0$ and $bx - 2ay - 3a = 0$,where $(a, b) \ne (0, 0)$ is