If the lines $\frac{x-3}{2}=\frac{y-2}{3}=\frac{z-1}{\lambda}$ and $\frac{x-2}{3}=\frac{y-3}{2}=\frac{z-2}{3}$ are coplanar,then $\sin ^{-1}(\sin \lambda)+\cos ^{-1}(\cos \lambda)=$

  • A
    $8-2\pi$
  • B
    $6-\pi$
  • C
    $3\pi -8$
  • D
    $4\pi -8$

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