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(A) The given circle is $x^2+y^2=4$,which can be written as $x^2+y^2=2^2$. This represents a circle with center at the origin $(0,0)$ and radius $r=2$

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$x+y=2$

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(A) The given circle is $x^2+y^2=4$,which can be written as $x^2+y^2=2^2$. This represents a circle with center at the origin $(0,0)$ and radius $r=2$. From the figure,the lines joining the origin to the points of intersection of line $L$ and the circle are the coordinate axes. The points of intersection are $A(2,0)$ and $B(0,2)$. The equation of the line $L$ passing through $(2,0)$ and $(0,2)$ is given by the intercept form: $\frac{x}{a}+\frac{y}{b}=1$. Substituting $a=2$ and $b=2$,we get $\frac{x}{2}+\frac{y}{2}=1$,which simplifies to $x+y=2$.

If the lines joining the origin to the points of intersection of a line $L$ and $x^2+y^2=4$ are the coordinate axes,then the equation of the line $L$ is

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