If the mean of the numbers 27 + x,31 + x,89 + | vedclass

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(A) Given that the mean of the numbers $27 + x, 31 + x, 89 + x, 107 + x, 156 + x$ is $82$.$\frac{(27 + x) + (31 + x) + (89 + x) + (107 + x) + (156 + x

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$75$

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(A) Given that the mean of the numbers $27 + x, 31 + x, 89 + x, 107 + x, 156 + x$ is $82$.$\frac{(27 + x) + (31 + x) + (89 + x) + (107 + x) + (156 + x)}{5} = 82$$\frac{410 + 5x}{5} = 82$$82 + x = 82$$x = 0$Now,we need to find the mean of $130 + x, 126 + x, 68 + x, 50 + x, 1 + x$.Mean $= \frac{(130 + x) + (126 + x) + (68 + x) + (50 + x) + (1 + x)}{5}$Mean $= \frac{375 + 5x}{5} = 75 + x$Since $x = 0$,the mean is $75 + 0 = 75$.

$x_i$	$5$	$15$	$25$	$35$	$45$	$55$
$f_i$	$12$	$18$	$27$	$20$	$17$	$6$

If the mean of the numbers $27 + x$,$31 + x$,$89 + x$,$107 + x$,and $156 + x$ is $82$,then the mean of $130 + x$,$126 + x$,$68 + x$,$50 + x$,and $1 + x$ is:

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