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(C) The centroid of a triangle is the same as the centroid of the triangle formed by joining the midpoints of its sides.Let the midpoints be $(x_1, y_

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$(2, 5/3)$

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(C) The centroid of a triangle is the same as the centroid of the triangle formed by joining the midpoints of its sides.Let the midpoints be $(x_1, y_1) = (-2, 3)$,$(x_2, y_2) = (4, -3)$,and $(x_3, y_3) = (4, 5)$.The centroid $(G)$ is given by the formula:$G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)$Substituting the values:$G = \left( \frac{-2 + 4 + 4}{3}, \frac{3 - 3 + 5}{3} \right)$$G = \left( \frac{6}{3}, \frac{5}{3} \right)$$G = \left( 2, \frac{5}{3} \right)$Thus,the correct option is $(C)$.

If the midpoints of the sides of a triangle are $(-2, 3), (4, -3)$ and $(4, 5)$,then the centroid of the triangle is

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