If the midpoint of the line segment joining P | vedclass

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Question

(B) The midpoint formula for a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\r

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) The midpoint formula for a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$.Given the points $P(3, 4)$ and $Q(a, 8)$,the midpoint $M$ is $\left(\frac{3 + a}{2}, \frac{4 + 8}{2}\right)$.We are given that the midpoint is $M(5, 6)$.Equating the coordinates,we get $\frac{3 + a}{2} = 5$ and $\frac{4 + 8}{2} = 6$.From the first equation,$3 + a = 10$,which implies $a = 10 - 3 = 7$.Thus,the value of $a$ is $7$.

If the midpoint of the line segment joining $P(3, 4)$ and $Q(a, 8)$ is $M(5, 6)$,then $a = \ldots \ldots \ldots \ldots$

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