If the number of moles of Fe^{2+} ions oxidiz | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The oxidation of $Fe^{2+}$ to $Fe^{3+}$ involves the loss of $1$ electron: $Fe^{2+} \rightarrow Fe^{3+} + e^-$.For $MnO_4^-$ in acidic medium: $Mn

Vedclass · Accepted Answer

$\frac{6x}{5}$

Vedclass · Answer

(B) The oxidation of $Fe^{2+}$ to $Fe^{3+}$ involves the loss of $1$ electron: $Fe^{2+} \rightarrow Fe^{3+} + e^-$.For $MnO_4^-$ in acidic medium: $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$. Thus, $1$ mole of $MnO_4^-$ oxidizes $5$ moles of $Fe^{2+}$. Given $x = 5$.For $Cr_2O_7^{2-}$ in acidic medium: $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$. Thus, $1$ mole of $Cr_2O_7^{2-}$ oxidizes $6$ moles of $Fe^{2+}$.Since $x = 5$, the number of moles of $Fe^{2+}$ oxidized by $Cr_2O_7^{2-}$ is $6$. Expressing $6$ in terms of $x$: $6 = \frac{6x}{5}$.

If the number of moles of $Fe^{2+}$ ions oxidized by one mole of acidified $MnO_4^{-}$ is $x$, the number of moles of $Fe^{2+}$ ions oxidized by one mole of acidified $Cr_2O_7^{2-}$ is:

Similar Questions

$H^{+} + Cr_2O_7^{2-} + SO_3^{2-} \to Cr^{3+} + SO_4^{2-} + H_2O$. In the balanced reaction,the coefficients of $H^{+}$ and $SO_4^{2-}$ will be respectively:

The reaction of sulphur in alkaline medium is given below:
$S_{8(s)} + a OH^{-}_{(aq)} \rightarrow b S^{2-}_{(aq)} + c S_{2}{O_{3}}^{2-}_{(aq)} + d H_{2}O_{(\ell)}$
The value of '$a$' is ............ (Integer answer)

The number of moles of $K_2Cr_2O_7$ reduced by $1 \ mol$ of $Sn^{+2}$ is:

Consider a titration of potassium dichromate solution with acidified Mohr's salt solution using diphenylamine as indicator. The number of moles of Mohr's salt required per mole of dichromate is

Which of the following reactions is a metal displacement reaction? Choose the right option.

Vedclass Test Series

Exam Paper Generator

Online Exam Module