(B) The given equation of the pair of straight lines is $xy-x-y+1=0$.Factoring the expression: $x(y-1)-1(y-1)=0$,which gives $(x-1)(y-1)=0$.This repre

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(B) The given equation of the pair of straight lines is $xy-x-y+1=0$.Factoring the expression: $x(y-1)-1(y-1)=0$,which gives $(x-1)(y-1)=0$.This represents two lines: $x=1$ and $y=1$.The point of intersection of these two lines is $(1, 1)$.Since the lines are concurrent with the line $ax+2y-3a=0$,the point $(1, 1)$ must satisfy the equation of the line $ax+2y-3a=0$.Substituting $x=1$ and $y=1$ into the equation: $a(1)+2(1)-3a=0$.$a+2-3a=0$.$-2a+2=0$.$2a=2$.$a=1$.

Class 11 Mathematics Pair of straight lines Bisectors of the angle between the lines, Point of intersection of the lines

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If the pair of straight lines $xy-x-y+1=0$ and the line $ax+2y-3a=0$ are concurrent,then $a$ is equal to

TS EAMCET 2002 All TS EAMCET

AP EAMCET 2002 All AP EAMCET

A
$0$
B
$1$
C
$-1$
D
$3$

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Pair of straight lines

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Bisectors of the angle between the lines, Point of intersection of the lines

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If the pair of straight lines $xy-x-y+1=0$ and the line $ax+2y-3a=0$ are concurrent,then $a$ is equal to

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