If the point (lambda, 1+lambda) lies inside t | vedclass

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(C) For a point $(x_1, y_1)$ to lie inside the circle $x^2+y^2-r^2=0$,the condition is $x_1^2+y_1^2-r^2 < 0$. Given the point $(\lambda, 1+\lambda)$ a

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$-1 < \lambda < 0$

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(C) For a point $(x_1, y_1)$ to lie inside the circle $x^2+y^2-r^2=0$,the condition is $x_1^2+y_1^2-r^2 Given the point $(\lambda, 1+\lambda)$ and the circle $x^2+y^2-1=0$,we substitute the point into the equation: $\lambda^2 + (1+\lambda)^2 - 1 $\lambda^2 + 1 + 2\lambda + \lambda^2 - 1 $2\lambda^2 + 2\lambda $2\lambda(\lambda+1) Dividing by $2$,we get $\lambda(\lambda+1) This inequality holds when $\lambda$ lies between the roots $-1$ and $0$. Therefore,$-1 < \lambda < 0$.

If the point $(\lambda, 1+\lambda)$ lies inside the circle $x^2+y^2=1$,then

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