If the point $\left(\frac{k-1}{k}, \frac{k-2}{k}\right)$ lies on the locus of $z$ satisfying the inequality $\left|\frac{z+3i}{3z+i}\right| < 1$,then the interval in which $k$ lies is

  • A
    $(-\infty, 2) \cup (3, \infty)$
  • B
    $[2, 3]$
  • C
    $[1, 5]$
  • D
    $(-\infty, 1) \cup (5, \infty)$

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