If the position vectors of the vertices of a $\triangle ABC$ are $\vec{OA} = 3\hat{i} + \hat{j} + 2\hat{k}$,$\vec{OB} = \hat{i} + 2\hat{j} + 3\hat{k}$ and $\vec{OC} = 2\hat{i} + 3\hat{j} + \hat{k}$,then the length of the altitude of $\triangle ABC$ drawn from $A$ is

  • A
    $\sqrt{\frac{3}{2}}$
  • B
    $\frac{3}{\sqrt{2}}$
  • C
    $\frac{\sqrt{3}}{2}$
  • D
    $\frac{3}{2}$

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