If the pressure on a body is increased from $200 \text{ kPa}$ to $250 \text{ kPa}$,the volume of the body decreases by $0.25 \%$. The compressibility of the material of the body is (in $m^2 \text{ N}^{-1}$)

$A$ ball is taken to a depth of $200 \ m$ in a lake. The decrease in its volume is $0.1\%$. Calculate the bulk modulus of the material of the ball.

For a constant hydraulic stress on an object,the fractional change in the object's volume $(\Delta V/V)$ and its bulk modulus $(B)$ are related as

$1\, m^3$ of water is brought inside a lake up to a depth of $200\, m$ from the surface. What will be the change in volume if the bulk modulus of elasticity of water is $22000\, \text{atm}$? (Given: density of water $\rho = 1\times10^3\, kg/m^3$, atmospheric pressure $P_0 = 10^5\, N/m^2$, and $g = 10\, m/s^2$)

$A$ spherical ball contracts in volume by $0.02 \%$, when subjected to a normal uniform pressure of $50 \text{ atm}$. The Bulk modulus of its material is ............. $Nm^{-2}$. (Take $1 \text{ atm} = 1.01 \times 10^5 \text{ Pa}$)

Why is water more elastic than air?