(C) For a quadratic equation $ax^2 + bx + c = 0$,the product of the roots is given by $\frac{c}{a}$.Given the equation $mx^2 + 6x + (2m - 1) = 0$,we h

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(C) For a quadratic equation $ax^2 + bx + c = 0$,the product of the roots is given by $\frac{c}{a}$.Given the equation $mx^2 + 6x + (2m - 1) = 0$,we have $a = m$ and $c = 2m - 1$.The product of the roots is given as $-1$.Therefore,$\frac{2m - 1}{m} = -1$.Multiplying both sides by $m$,we get $2m - 1 = -m$.Adding $m$ to both sides,we get $3m - 1 = 0$.Thus,$3m = 1$,which gives $m = \frac{1}{3}$.

Class 11 Mathematics 2 Complex Numbers and Quadratic Equations: Quadratic Equations Relation between roots and coefficients

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If the product of roots of the equation $mx^2 + 6x + (2m - 1) = 0$ is $-1$,then the value of $m$ will be

A
$1$
B
$-1$
C
$\frac{1}{3}$
D
$-\frac{1}{3}$

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Relation between roots and coefficients

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