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(A) The volume $V$ of a sphere with radius $r$ is given by the formula $V = \frac{4}{3} \pi r^3$.If the radius is doubled,the new radius $r' = 2r$.The

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$8$

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(A) The volume $V$ of a sphere with radius $r$ is given by the formula $V = \frac{4}{3} \pi r^3$.If the radius is doubled,the new radius $r' = 2r$.The new volume $V'$ is given by $V' = \frac{4}{3} \pi (r')^3$.Substituting $r' = 2r$ into the formula,we get $V' = \frac{4}{3} \pi (2r)^3 = \frac{4}{3} \pi (8r^3) = 8 	imes (\frac{4}{3} \pi r^3)$.Therefore,$V' = 8V$.Thus,the volume becomes $8$ times the original volume.

If the radius of a sphere is doubled,its volume becomes $\ldots \ldots \ldots \ldots$ times the original volume.

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