If the radius of a sphere is increased by 2 , | vedclass

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(D) Let the radius of the original sphere be $r \, m$.The new radius is $(r + 2) \, m$.The surface area of a sphere is given by $A = 4 \pi r^2$.Accord

Vedclass · Accepted Answer

$13$

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(D) Let the radius of the original sphere be $r \, m$.The new radius is $(r + 2) \, m$.The surface area of a sphere is given by $A = 4 \pi r^2$.According to the problem,the increase in surface area is $704 \, m^2$:$4 \pi (r + 2)^2 - 4 \pi r^2 = 704$Divide by $4 \pi$:$(r + 2)^2 - r^2 = \frac{704}{4 \pi}$$(r^2 + 4r + 4) - r^2 = \frac{176}{\pi}$$4r + 4 = \frac{176}{22/7}$$4(r + 1) = \frac{176 	imes 7}{22}$$4(r + 1) = 8 	imes 7$$4(r + 1) = 56$$r + 1 = 14$$r = 13 \, m$.

If the radius of a sphere is increased by $2 \, m$,its surface area is increased by $704 \, m^2$. What is the radius of the original sphere? (in $m$)
(use $\pi = \frac{22}{7}$)

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If the radius of a sphere is increased by $2 \, m$,its surface area is increased by $704 \, m^2$. What is the radius of the original sphere? (in $m$)(use $\pi = \frac{22}{7}$)