If the radius of a sphere is measured as $9 \ cm$ with an error of $0.03 \ cm$, then find the approximate error in calculating its surface area. (in $\pi \ cm^2$)

If the radius of a sphere is measured as $9 \text{ cm}$ with an error of $0.03 \text{ cm}$,then find the approximate error in calculating its volume. (in $\pi \text{ cm}^3$)

The radius of a cone of height $9 \text{ units}$ is changed from $2 \text{ units}$ to $2.12 \text{ units}$. The exact change and approximate change in the volume of the cone are respectively:

The approximate change in the volume of a cube of side $x$ metres caused by increasing the side by $3 \%$ is (in $x^{3} \text{ m}^{3}$)

The approximate value of $y=(1.01)^3+2(1.01)^{\frac{3}{2}}+5$ is

The approximate value of $\sqrt[3]{730}$ obtained by the application of derivatives is