If the radius of the Earth shrinks by 1.5 % ( | vedclass

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(C) The gravitational acceleration $g$ is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Ear

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$3$

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(C) The gravitational acceleration $g$ is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Earth,and $R$ is its radius.Since the mass $M$ remains constant,we have $g \propto \frac{1}{R^2}$.Taking the logarithmic derivative,we get $\frac{\Delta g}{g} = -2 \frac{\Delta R}{R}$.Given that the radius shrinks by $1.5 \%$,we have $\frac{\Delta R}{R} = -1.5 \% = -0.015$.Substituting this value into the equation:$\frac{\Delta g}{g} = -2 	imes (-1.5 \%) = +3 \%$.Therefore,the gravitational acceleration increases by $3 \%$.

If the radius of the Earth shrinks by $1.5 \%$ (mass remaining same),then the value of gravitational acceleration changes by ......... $\%$

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