If the radius of the spherical Gaussian surface is increased,then the electric flux due to a point charge enclosed by the surface:

If charge $q$ is placed on one of the vertex of a cube, then total electric flux passing through the cube is . . . . . . .

$A$ point charge $+Q$ is placed just outside an imaginary hemispherical surface of radius $R$ as shown in the figure. Which of the following statements is/are correct?
$[A]$ The electric flux passing through the curved surface of the hemisphere is $-\frac{Q}{2 \varepsilon_0}\left(1-\frac{1}{\sqrt{2}}\right)$
$[B]$ Total flux through the curved and the flat surfaces is $\frac{Q}{\varepsilon_0}$
$[C]$ The component of the electric field normal to the flat surface is constant over the surface
$[D]$ The circumference of the flat surface is an equipotential

Total electric flux coming out of a unit positive charge placed in air is

The figure shows the electric field lines around three point charges $A, B$,and $C$.
$(a)$ Which charges are positive?
$(b)$ Which charge has the largest magnitude? Why?
$(c)$ In which region or regions of the picture could the electric field be zero? Justify your answer.
$(i)$ Near $A$ $(ii)$ Near $B$ $(iii)$ Near $C$ $(iv)$ Nowhere

Consider the integral form of the Gaussian law in electrostatics: $\oint \vec{E} \cdot d\vec{s} = \frac{Q}{\epsilon_0}$. Which of the following statements are correct?