Total electric flux coming out of a unit positive charge placed in air is

$A$ point charge $q$ is placed at a distance $a/2$ directly above the center of a square of side $a$. The electric flux through the square is:

The electric field in the region is $\vec{E} = a\hat{i} + b\hat{j}$ where $a$ and $b$ are constants. The net electric flux passing through a square area of side $l$ parallel to the $Y-Z$ plane is

The dimensional formula of electric flux is . . . . . . .

$A$ point charge causes an electric flux of $-1.0 \times 10^{3} \; N \cdot m^{2} / C$ to pass through a spherical Gaussian surface of $10.0 \; cm$ radius centered on the charge.
$(a)$ If the radius of the Gaussian surface were doubled,how much flux would pass through the surface?
$(b)$ What is the value of the point charge?

$A$ charge is kept at the central point $P$ of a cylindrical region. The two edges subtend a half-angle $\theta$ at $P$, as shown in the figure. When $\theta=30^{\circ}$, then the electric flux through the curved surface of the cylinder is $\Phi$. If $\theta=60^{\circ}$, then the electric flux through the curved surface becomes $\Phi / \sqrt{n}$, where the value of $n$ is. . . . . . .