If the radius ratio for an ionic solid is $0.5248$ and the radius of the cation is $0.95 \ \mathring{A}$,what is the radius of the anion?

  • A
    $1.45 \ \mathring{A}$
  • B
    $1.81 \ \mathring{A}$
  • C
    $1.20 \ \mathring{A}$
  • D
    $1.60 \ \mathring{A}$

Explore More

Similar Questions

An ionic solid $AB$ crystallizes in a $NaCl$-type structure,where $A$ ions are at the corners of the cube. If all face-centered ions along one axis are removed,then the stoichiometry of the resulting solid will be .....

Difficult
View Solution

Predict the close-packed structure of an ionic compound $A^{+} B^{-}$ in which the radius of cation and anion are $148 \ pm$ and $195 \ pm$ respectively.

An ionic compound is expected to have a tetrahedral structure if the radius ratio $r_{+} / r_{-}$ lies in the range of:

What are the coordination numbers of $bcc$,$scc$,and $fcc$ respectively?

In the $NaCl$ structure,what is the position of $Cl^-$ ions?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo