If the range of the function f(x) = -3x - 3 i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The function is given by $f(x) = -3x - 3$. To find the domain,we set $f(x) = y$ and solve for $x$: $y = -3x - 3$ $y + 3 = -3x$ $x = \frac{y + 3}{-

Vedclass · Accepted Answer

$-1$

Vedclass · Answer

(A) The function is given by $f(x) = -3x - 3$. To find the domain,we set $f(x) = y$ and solve for $x$: $y = -3x - 3$ $y + 3 = -3x$ $x = \frac{y + 3}{-3} = -\frac{y}{3} - 1$. Given the range values $y \in \{3, -6, -9, -18\}$,we calculate the corresponding domain values $x$: For $y = 3$,$x = -\frac{3}{3} - 1 = -1 - 1 = -2$. For $y = -6$,$x = -\frac{-6}{3} - 1 = 2 - 1 = 1$. For $y = -9$,$x = -\frac{-9}{3} - 1 = 3 - 1 = 2$. For $y = -18$,$x = -\frac{-18}{3} - 1 = 6 - 1 = 5$. The domain is $\{-2, 1, 2, 5\}$. Comparing this with the given options,$-1$ is not in the domain.

If the range of the function $f(x) = -3x - 3$ is $\{3, -6, -9, -18\}$,then which one of the following is not in the domain of $f$?

Similar Questions

The domain of the function $f(x) = \sqrt{\log_e\left(\frac{1}{x^2-4x+4}\right)} + \sin^{-1}(x^2-2)$ is

The function $f: R \rightarrow R$ is defined by $f(x) = \cos^2 x + \sin^4 x$ for $x \in R$. Then $f(R)$ is equal to:

The domain of definition of the function $f(x)$ given by the equation $2^x + 2^y = 2$ is

If $R-(\alpha, \beta)$ is the range of $\frac{x+3}{(x-1)(x+2)}$,then the sum of the intercepts of the line $\alpha x+\beta y+1=0$ on the coordinate axes is

If $f(x) = [x]^{2} - 5[x] + 6 = 0$,where $[x]$ denotes the greatest integer function,then $x \in$

Vedclass Test Series

Exam Paper Generator

Online Exam Module