If the refractive indices of crown glass for | vedclass

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(B) The dispersive power $(\omega)$ of a material is defined as the ratio of the angular dispersion for the extreme colours (violet and red) to the me

Vedclass · Accepted Answer

$\frac{\mu_v - \mu_r}{\mu_y - 1}$

Vedclass · Answer

(B) The dispersive power $(\omega)$ of a material is defined as the ratio of the angular dispersion for the extreme colours (violet and red) to the mean deviation produced by the prism.Mathematically,it is expressed as:$\omega = \frac{\delta_v - \delta_r}{\delta_y}$Since the deviation $\delta$ produced by a thin prism is given by $\delta = (\mu - 1)A$,where $A$ is the angle of the prism,we substitute this into the formula:$\omega = \frac{(\mu_v - 1)A - (\mu_r - 1)A}{(\mu_y - 1)A}$Simplifying the expression by cancelling $A$:$\omega = \frac{\mu_v - 1 - \mu_r + 1}{\mu_y - 1}$$\omega = \frac{\mu_v - \mu_r}{\mu_y - 1}$Therefore,the correct option is $B$.

If the refractive indices of crown glass for red,yellow,and violet colours are respectively $\mu_r$,$\mu_y$,and $\mu_v$,then the dispersive power of this glass would be

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