The refractive index of flint glass for blue | vedclass

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Question

(A) The dispersive power $\omega$ is given by the formula $\omega = \frac{\mu_V - \mu_R}{\mu_y - 1}$.Given: $\mu_V = 1.6333$ (blue) and $\mu_R = 1.616

Vedclass · Accepted Answer

$0.0276$

Vedclass · Answer

(A) The dispersive power $\omega$ is given by the formula $\omega = \frac{\mu_V - \mu_R}{\mu_y - 1}$.Given: $\mu_V = 1.6333$ (blue) and $\mu_R = 1.6161$ (red).The mean refractive index $\mu_y$ is calculated as $\mu_y = \frac{\mu_V + \mu_R}{2} = \frac{1.6333 + 1.6161}{2} = 1.6247$.Now,substitute the values into the formula:$\omega = \frac{1.6333 - 1.6161}{1.6247 - 1} = \frac{0.0172}{0.6247} \approx 0.02753$.Rounding to the nearest provided option,we get $\omega = 0.0276$.

The refractive index of flint glass for blue light is $1.6333$ and for red light is $1.6161$. Calculate the dispersive power of the prism,assuming the mean refractive index is approximately the average of the two given values.

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