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(B) Let the dimension of the gravitational constant be $[G] = [c^x g^y p^z]$.The dimensions of the given quantities are:$[G] = [M^{-1} L^3 T^{-2}]$$[c

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$c^0 g^2 p^{-1}$

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(B) Let the dimension of the gravitational constant be $[G] = [c^x g^y p^z]$.The dimensions of the given quantities are:$[G] = [M^{-1} L^3 T^{-2}]$$[c] = [L T^{-1}]$$[g] = [L T^{-2}]$$[p] = [M L^{-1} T^{-2}]$Substituting these into the equation:$[M^{-1} L^3 T^{-2}] = [L T^{-1}]^x [L T^{-2}]^y [M L^{-1} T^{-2}]^z$$[M^{-1} L^3 T^{-2}] = [M^z L^{x+y-z} T^{-x-2y-2z}]$Comparing the powers of $M, L,$ and $T$ on both sides:For $M$: $z = -1$For $L$: $x + y - z = 3 \implies x + y - (-1) = 3 \implies x + y = 2$For $T$: $-x - 2y - 2z = -2 \implies -x - 2y - 2(-1) = -2 \implies -x - 2y = -4 \implies x + 2y = 4$Solving the equations:$(x + 2y) - (x + y) = 4 - 2 \implies y = 2$$x + 2 = 2 \implies x = 0$Thus,$[G] = [c^0 g^2 p^{-1}]$.

If the speed of light $(c)$,acceleration due to gravity $(g)$,and pressure $(p)$ are taken as the fundamental quantities,then the dimension of the gravitational constant $(G)$ is:

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