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(B) The energy released in an atomic explosion is given by Einstein's mass-energy equivalence relation: $E = \Delta m C^2$.Let the original speed of l

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(B) The energy released in an atomic explosion is given by Einstein's mass-energy equivalence relation: $E = \Delta m C^2$.Let the original speed of light be $C$ and the new speed of light be $C' = \frac{2}{3} C$.The new energy released $E'$ is given by: $E' = \Delta m (C')^2$.Substituting the value of $C'$: $E' = \Delta m \left(\frac{2}{3} Cight)^2 = \Delta m \left(\frac{4}{9} C^2ight) = \frac{4}{9} E$.The fraction by which the energy is decreased is given by: $	ext{Fraction} = \frac{E - E'}{E}$.Substituting $E' = \frac{4}{9} E$: $	ext{Fraction} = \frac{E - \frac{4}{9} E}{E} = \frac{\frac{5}{9} E}{E} = \frac{5}{9}$.

If the speed of light were $2/3$ of its present value,the energy released in a given atomic explosion will be decreased by a fraction:

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