One million electron volt $(1\,MeV)$ is equal to

  • A
    $10^5\,eV$
  • B
    $10^6\,eV$
  • C
    $10^4\,eV$
  • D
    $10^7\,eV$

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When the atomic number $A$ of the nucleus increases,

One requires energy ${E_n}$ to remove a nucleon from a nucleus and an energy ${E_e}$ to remove an electron from the orbit of an atom. Then:

Nucleus $A$ has a mass number of $220$ and its binding energy per nucleon is $5.6 \, MeV$. It splits into two fragments '$B$' and '$C$' with mass numbers $105$ and $115$,respectively. The binding energy per nucleon for both '$B$' and '$C$' is $6.4 \, MeV$. The energy $Q$ released per fission will be............$MeV$.

The energy equivalent to a mass of $1 \,kg$ is

The energy in $MeV$ released due to the complete transformation of $1\, kg$ of mass into energy is $(c = 3 \times 10^8\, m/s)$:

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