When the atomic number $A$ of the nucleus increases,

The mass of ${ }_7 N ^{15}$ is $15.00011 \ amu$,the mass of ${ }_8 O ^{16}$ is $15.99492 \ amu$,and $m_p = 1.00783 \ amu$. Determine the binding energy of the last proton of ${ }_8 O ^{16}$ in $MeV$.

The atomic mass of ${ }_7 N ^{15}$ is $15.000108 \text{ a.m.u.}$ and that of ${ }_8 O ^{16}$ is $15.994915 \text{ a.m.u.}$ If the mass of a proton is $1.007825 \text{ a.m.u.}$,then the minimum energy required to remove the least tightly bound proton is ......... $MeV$.

What is the order of binding energy per nucleon?

$m_{p}$ and $m_{n}$ are the masses of a proton and a neutron, respectively. For an element of mass $M$ having $Z$ protons and $N$ neutrons, which of the following is true?

For a nucleus ${ }_Z^A X$ having mass number $A$ and atomic number $Z$:
$A.$ The surface energy per nucleon $(b_s) = a_1 A^{2/3}$
$B.$ The Coulomb contribution to the binding energy $b_c = -a_2 \frac{Z(Z-1)}{A^{4/3}}$
$C.$ The volume energy $b_v = a_3 A$
$D.$ Decrease in the binding energy is proportional to surface area.
$E.$ While estimating the surface energy,it is assumed that each nucleon interacts with $12$ nucleons,($a_1, a_2$ and $a_3$ are constants)
Choose the most appropriate answer from the options given below: