If the sum of the first $n$ terms of an $A.P.$ is $c n^2$,then the sum of the squares of these $n$ terms is

  • A
    $\frac{n(4 n^2-1) c^2}{6}$
  • B
    $\frac{n(4 n^2+1) c^2}{3}$
  • C
    $\frac{n(4 n^2-1) c^2}{3}$
  • D
    $\frac{n(4 n^2+1) c^2}{6}$

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