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(D) The given equation is $x^2 - 2xy 	an A - y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we have $a = 1$,$2h = -2 	an A$,

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$	an^{-1}(-2)$

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(D) The given equation is $x^2 - 2xy 	an A - y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we have $a = 1$,$2h = -2 	an A$,and $b = -1$.Let the slopes of the lines be $m_1$ and $m_2$.The sum of the slopes is given by $m_1 + m_2 = -\frac{2h}{b}$.Substituting the values,we get $m_1 + m_2 = -\frac{-2 	an A}{-1} = -2 	an A$.Given that the sum of the slopes is $4$,we have $-2 	an A = 4$.Therefore,$	an A = -2$,which implies $A = 	an^{-1}(-2)$.

If the sum of the slopes of the lines represented by the equation $x^2 - 2xy \tan A - y^2 = 0$ is $4$,then $\angle A = $

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