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(C) The distance of a point $P(x, y, z)$ from the $x$-axis is $\sqrt{y^2 + z^2}$.The distance of point $P$ from the $y$-axis is $\sqrt{x^2 + z^2}$.The

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$9 \sqrt{2}$

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(C) The distance of a point $P(x, y, z)$ from the $x$-axis is $\sqrt{y^2 + z^2}$.The distance of point $P$ from the $y$-axis is $\sqrt{x^2 + z^2}$.The distance of point $P$ from the $z$-axis is $\sqrt{x^2 + y^2}$.Given that the sum of the squares of these distances is $324$:$(y^2 + z^2) + (x^2 + z^2) + (x^2 + y^2) = 324$$2(x^2 + y^2 + z^2) = 324$$x^2 + y^2 + z^2 = 162$The distance of point $P(x, y, z)$ from the origin $(0, 0, 0)$ is given by $d = \sqrt{x^2 + y^2 + z^2}$.Substituting the value,we get $d = \sqrt{162} = \sqrt{81 	imes 2} = 9 \sqrt{2}$.

If the sum of the squares of the distances of a point $P(x, y, z)$ from the three co-ordinate axes is $324$,then the distance of point $P$ from the origin is ....

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