If the temperature of a gas is increased from $27^{\circ} C$ to $159^{\circ} C$, then the percentage increase in the $rms$ speed of the gas molecules is

The temperature of a gas is $-73^{\circ}C$. To what temperature should the gas be heated so that the $rms$ speed of the molecules is doubled (in $^{\circ}C$)?

If the molecular weights of two gases are $M_1$ and $M_2$,then at a constant temperature,the ratio of their root mean square velocities $v_1$ and $v_2$ will be:

$N$ molecules each of mass $m$ of gas $A$ and $2N$ molecules each of mass $2m$ of gas $B$ are contained in a vessel which is maintained at temperature $T$. The mean square velocity of the molecules of gas $B$ is denoted by $V_2^2$ and the mean square of the $X$-component velocity of the molecules of gas $A$ is denoted by $V_1^2$, then $\frac{V_1}{V_2}$ is

The temperature at which oxygen molecules will have the same r.m.s. speed as helium molecules at $57^{\circ} C$ is (molecular masses of oxygen and helium are $32$ and $4$ respectively.) (in $K$)

Why does the movement (motion) of gas molecules become zero at absolute zero temperature?