If the temperature of the sun becomes twice i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Wien's Displacement Law,the wavelength corresponding to the maximum emission of radiation is inversely proportional to the absolute t

Vedclass · Accepted Answer

Radiated energy would be predominantly in ultraviolet

Vedclass · Answer

(B) According to Wien's Displacement Law,the wavelength corresponding to the maximum emission of radiation is inversely proportional to the absolute temperature: ${\lambda _{max}} \propto \frac{1}{T}$.Given that the current temperature of the sun is $T$,the wavelength of maximum emission is ${\lambda _{max}} \approx 4753 \mathring{A}$,which lies in the visible region (near violet).If the temperature becomes $T' = 2T$,the new wavelength of maximum emission will be ${\lambda '_{max}} = \frac{{\lambda _{max}}}{2} = \frac{4753 \mathring{A}}{2} \approx 2376.5 \mathring{A}$.Since this wavelength is shorter than the visible range,the radiated energy will be predominantly in the ultraviolet region.

If the temperature of the sun becomes twice its present temperature,then

Similar Questions

The emissive power of a sphere of area $0.04 \,m^2$ is $0.7 \,kcal \,s^{-1} \,m^{-2}$. The amount of heat radiated in $20 \,s$ is: (in $\,kcal$)

The Earth radiates in the infra-red region of the spectrum. The spectrum is correctly given by

Two stars $P$ and $Q$ are observed at night. Star $P$ appears reddish while star $Q$ is white. From this we conclude:

The wavelength of radiation emitted by a body depends upon

Two stars $A$ and $B$ radiate maximum energy at the wavelengths of $360 \ nm$ and $480 \ nm$ respectively. Then the ratio of the surface temperatures of $A$ and $B$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module